WAEC-PHYSICS-ALT B-ANSWERS
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Solution Before Exam Time.
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WAEC-PHYSICS-ALT B-ANSWERS
(2a)
Tabulate
S/n; 1,2,3,4,5

U(cm); 25.00,30.00,35.00,40.00,45.00

V(cm); 99.00,61.00,46.00,40.00,36.00

M,=u/v; 3.960,2.033,1.314,1.000,0.800

M-¹; 0.253,0.492,0.761,1.000,1.250

(2graph)

(2xii)
(i)I ensure I avoided parallax error in reading the meter rule
(ii)I ensured the Practical was done in a dark room

(2bi)
Between the principal focus and the lens

(2bii)
Erect image is ritual
1/u-1/v=1/f
1/u-1/30=1/15
1/u=1/15+1/30
1/u=2+1/30
1/u=30/30
u=30/3
u=10
m=V/u=30/10
=3
The image is 3times bigger
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(3ai)
TABULATE
S/N 1|2|3|4|5|

R(ohm)|1.00| 2.00| 3.00|4.00|5.00|

I(A) |0.55|0.40|0.33|0.35|0.30|

V(v) |0.65|0.50|0.45|0.42|0.40|

(3aviii)
Precautions
(i) I ensured tight connection of wires
(ii) I ensured that i avoided parallax error in reading ammeter and voltmeter reading

(3graph)

(3bi)
(i)Length of the wire
(ii)Cross sectional area of the wire
(iii)Temperature of the wire
(iv)Material the wire is made of

(3bii)
View image
V=IR
1.2= 0.6 × R
R=1.2/0.6
R=2ohm
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(1bi)
Archimedes’ principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.

(1bii)
Man of the body in water =60g
Man of the body when attached with object =61g
Man of the object and the body in water =59g
R.D of object =61-59/61-60=2/1
R.D of object =200