WAEC-PHYSICS-PRACTICAL-ANSWERS
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WAEC-PHYSICS-PRACTICAL-ANSWERS

(1)
Graph!.

(1)
S|N; 1|2|3|4|5|

M(g); 40.0|60.0|80.0|100.0|120.0|

X(cm);37.50|25.01|8.75|15.00|12.50|

X-¹(cm-¹); 0.027| 0.040|0.|053|0.067|0.08|

X-¹(x10-³); 27.00|40.00|53.00|67.00|80.00|

G=50.0cm
Y=30.0cm

Slope =∆M/∆X^-1= M2-M1/(X^-1) – (X^-1)
S= 120.0 -40/80.0-27
S= 80/53
S=1.509*10^3
S=1509

(x)
S=ymo
1509=30mo
mo=1509/30
mo=50.3

(1xi)
(i)Measure readings accurately
(ii)Avoid error due to parallax
(1bii)
CWM = ACWM
60*25 = x *30
30x = 1500
Divide through by 30
30x/30 = 1500/30
x=50g

The mass that should be placed at the 80cm mark of the meter rule to balance it horizontally is 50g

(1)

(1bi)
Moment of a force can be defined as the product of the force and its perpendicular distance from its point of action.

(1bii)

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(3)
Graph!.

(3a)
(i)E=3.00v
Tabulate.
R(n); 1.0|2.0|4.0|6.0|8.0
I(A)0.40|0.35|0.28|0.22|0.18|
V(v)0.65|0.58|0.50|0 45|0.40|

(3bi)
(i) I avoided error due to parallax when reading the ammeter and voltmeter
(ii)I ensure tight connection.

(3bi)
(i)it increase current supplied
(ii)it makes up for any detect on any cells

(3bii)
(i)The length of the resistor.
(ii)The thickness of the resistor.
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