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(1a)
(1x)
Graph
(1xii)
(i)I avoided error due to parallax while reading the metre rule
(ii)I avoided zero error on the stop watch
(1bi)
The period of an oscillatory motion is the time taken for a body to complete one oscillation.
(1bii)
-TABULATE-
(i)Mass is a scalar quantity WHILE weight is a vector quantity.
(ii)The SI unit of mass is the kilogram (kg) WHILE the SI unit of weight is Newton (N).
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(3av)
Tabulate
S/N ||1 || 2 || 3 || 4 || 5
d(cm) || 80.00|| 70.00 || 50.00 || 40.00 || 30.00
I(A) || 0.30||0.35 || 0.40|| 0.45||0.50 ||
(I)^-¹ ||3.333 ||2.857 ||2.500 || 2.222||2.000 ||
(3avii)
from the graph, Slope s, = ∆d/∆I^-¹
= 71 – 20 ÷ 3 – 1.75
= 51/1.25
= 40.8cmA
Or 0.408Am
(3aviii)
(i) I ensured tight connections
(ii) I avoided error due to parallax while reading the ammeter
(3bi)
(i) Straight at the magnetic field
(ii) The number of turns of it’s coils
(3bii)
Given:
Diameter d, = 0.6cm = 6×10^-³m
Resistivity, e = 1.0×10^-6 Ωm
Resistance R = 4Ω
Using R = eL/A
L=RA/e
= Rπd²/4e
= 4 × 22/7 × 36 × 10^-6 ÷ 4 × 1 × 10^-⁶
= 22/7 × 36
= 113.14m
:. L = 113.14metres
(3a)
(3b)
(3iv)
Graph
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