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    Acurate-Maths-Obj

    1CCAACBADAB

    11BCCCBBBBBB

    21DDBDBCCCBA

    31BDDDCCCCCD

    41ACADADCDDC

    ================================

    Use this 100% CORRECT . IF YOU PAID AND U HAVE NOT RECIEVE ON WHATSAPP KINDLY ADD 09032305887 NOW !! TO GET IT .

    NO TIME

    Tips : Any u don’t see clear u click on d image and download it so that u can b able to resize it

    SOLUTIONCENTRE SHALL NEVER LET U DOWN.

    OBJ LOADING

    Maths-Theory

    PLS NOTE THIS SYMBOLS

    ^ means Raise to power

    * means multiplication

    √ means Sqr root

    / means division or divide

    SOLUTIONCENTRE SHALL NEVER LET U DOWN.

    ================================

    12a)

    9x+10=28

    9x=28-10

    9x=18

    x=18/9

    x=2

    -6x+4y=4

    -6(2)+4y=4

    4y=4+12

    4y=16

    y=16/4=4

    ================================

    13ai)

    x*y=x+y+2xy

    2*3=2+3+2*2*3

    =5+12=17

    (2*3)*5=17*5

    17+5+2*17*5

    =22+170=192

    ii)x*7=x+7+2(x)(7)

    =x+7+14x

    =15x+7

    x*5=x+5+2(x)(5)

    =x+5+10x

    =11x+5

    (x*5)*2=(11x+5)*2

    =11x+5+2+2(11x+5)^2

    =11x+5+2+44x+20

    =55x+27

    15x+7=55x+27

    15x-55x=22-7

    -40x=20

    x=-20/40=-1/2

    ================================

    2a)
    A=P(1+r/100)^n

    A=2,205,000

    n=2

    r=5%

    p=?

    2205000=p(1+5/100)^2

    2205000m=p(1.05)^2

    p=2205000/(1.05)^2=N2,000,000

    2b)

    area=30cm^2 h/b=3/2

    area=1/2bh

    b=2h/3

    30=1/2*2h/3*h

    2h^2=30*2*3

    h^2=30*2*3/2

    h^2=90

    h=√90=9.49m

    ================================

    4)area of shaded portion=area of sector pqs-area of triangle pqs

    =(θ/360*pieR^2)-(1/2r^2sinθ)

    (60/360*22/7*14^2)-(1/2*14^2sin60)

    102.2667-84.8705

    =17.796

    =17.8cm^2

    7a)
    log6Y+2log6x=3

    log6y+log6x^2=3

    log6(x^y)=3

    x^y=6^3

    x^y=216

    y=216/x^2

    7bi)

    draw

    7bii)

    percentage who liked football and volleyball but not boxing=20

    ii)percentage who liked exactly two part=40+20+10=70

    iii)summing

    5+5+10+40+20+10+5+x=100%

    x+95=100

    x=100-95=5%

    percentage who like none=5%

    ================================

    9a)

    diagrams

    9b)

    |CA|^2=300^2+100^2-2(300)(100)cos 120degree

    =9000+10000-60000(-cos60)

    =100000+30000

    KA|^2=130000

    KA|=√130000

    KA|=360.56KM

    9bii)

    Using sine rule

    |AB|/sinC=|AC|/sin120

    100/sinC=360.56

    sinC=100sin60/360.56

    sinC=0.2402

    C=sin^-1(0.2402)=13.90degree

    bearing=270+13.90=283.9degree = 284degree

    1a)
    [2(1/2)+1(3/4)/1(2/5)]/[2(1/4)-1(1/2)]

    [5/2+7/4/7/5]/[9/4-3/2]

    =[5/2+7/4*5/7]/[9/4-3/2]

    [5/2+5/4]/[9/4-3/2]

    =[(10+5/4)/(9-6/4)]

    =(15/4)/(3/4)

    =15/4*4/3

    =5

    1b)

    From tan60/1*PR/3root2

    PR=3root2*1/root3

    =3root2/root3*root3/root3

    =3root6/3=root6

    From sin45/1*root6/x

    x=root6*root2

    =root12

    =root4*3

    =2root3

    ================================

    5a)

    Daigrams

    5b)

    Median = ((N + 1) / 2)th item Where: N = 31

    40, 40, 40, 40, 40, 40, 40, 41, 41, 41, 41, 42, 42, 42, 42, 42, 42, 43, 43, 44, 44, 44, 44, 45, 45, 46, 46, 46, 46, 46, 46

    Data table

    F 7 4 6 2 4 2 6

    X 40 41 42 43 44 45 46

    Median = ((31 + 1) / 2)th item

    Median = (32 / 2)th item

    Median = 16th item

    Arranging the discrete data in ascending order, We go get:

    40, 40, 40, 40, 40, 40, 40, 41, 41, 41, 41, 42, 42, 42, 42, 42, 42, 43, 43, 44, 44, 44, 44, 45, 45, 46, 46, 46, 46, 46, 46

    Median = 42

    ================================

    3)

    2x/1 – 2/5 y = 2y/1

    LCM = 5

    10x – 2y = 10y

    10x = 10y + 2y

    10x = 12y

    X = 12y/10 ————-1

    2x – 2/5y + 2 1/4x + 1/2y + 2y = 180

    LCM = 20

    40x – 8y + 45x + 10y + 40y = 3600

    40x + 45x + 10y – 8y + 50y = 3600

    95x + 42y = 3600

    95 (6y/5) + 42y =3600

    19(6y) + 42y = 3600

    114y + 42y = 3600

    156y = 3600

    Y = 3600/156

    Y = 23.08

    Sub for y in eq 1

    X = 6(23.08)/5

    X = 27.69

    ================================

    11)

    A={4,5,6,7,8,9,10,11,12}

    B={10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}

    M={4,8,12,11,6,20,24,28}

    a)prob (A)=3/7

    b)prob( B)=7-4/7=3/7

    c)prob(AuB)=n(AuB)/n(m)

    but (AuB)={4,8,12,11,6,20,24,}

    prob(AuB)=6/7

    Maths-Theory

     

    ================================
    ================================

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